The higher the altitude, the thinner the air.
Conclusion
The air must be thinner in MC than in PC.
Evidence (since)
MC's altitude is higher than that of PC. The higher the altitude, the thinner the air.
Evaluate
There are repeating terms throughout, so it makes sense to try to write an Algebraic Recipe for this argument.
P1: The more X, the more Y. P2: A's got more X than B does. C: A's got more Y than B does.
A = mex city, B = pan city X = altitude, Y = air thinness
Goal
Let's look for something with the same logical structure.
discussion on Volume Dial statements (if you're interested) This seems like a valid argument. When we use a Volume Dial (aka Stepladder) formulation like "the more X, the more Y", it goes infinitely in both directions. You can also say "the less X, the less Y".
If the expression is couched in wording like, , then that indicates that reading newspapers has a positive influence on your LSAT ability, but it's not the only relevant factor, so you couldn't automatically assume that someone who's read 100 articles is better at LSAT than someone who's read 50.
The way the rule is presented here, it sounds like we can fairly judge that any higher altitude spot on Earth has thinner air. Although you might wonder whether it's meant to be interpreted as, .
But maybe some places on Earth with an altitude of 100m above sea level have an air thickness of 4 and other places with that same altitude have an air thickness of 5, because other local conditions influence how thin the air is.
Because of this ambiguity, it's not super clear whether this is airtight logic, but we should just worry about structure at first.