Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain.
Conclusion (it follows that)
M contains twice as many cans as L.
Evidence (since / and)
All cans have the same aluminum content, and they're basically nothing but aluminum.
All the cans from group L were recycled into cans in group M (all the same standard size).
50% of the aluminum in M came from L. (i.e. M has twice as much aluminum as L does)
Evaluate
This is definitely a dense argument to process. It fundamentally comes down to a mathematical equivalence.
If X is 50% of Y, then Y is twice as large as X.
A lot of Math-y argument play off of complementary percentages; an author might say . We know that 40% of people are not-X, but the author would be assuming "if you're not-X, then you're Y".
So this argument is essentially saying, if M has twice as much aluminum as L, then M is twice as many cans as L.
Let's that 10 kg of aluminum are used to make M. 5 kg (50% ) came from L.
If M is 100 cans, does that mean that L was 50 cans?
Apparently not! It seems like a tempting inference, but if were a logically guaranteed one, then they wouldn't be able to ask a Sufficient Assumption question. So we would probably want to go into Anti-Conclusion mode (very rare for Sufficient Assumption), and think to ourselves,
Given that ... M is twice as much aluminum as L How could we argue that ... M is NOT twice as many cans as L?
Goal
We might just have to live with being stumped by this paradox and head over to answers, seeking some hint about how we could possibly make this counterargument. (the correct answer would rule out such an objection)
Overall, we want an answer to convince us that .