An air traveler in Beijing cannot fly to Lhasa without first flying to Chengdu.
Conclusion (therefore)
Lhasa requires Xian (anyone who flies from Beijing to Lhasa cannot avoid flying to Xian).
Evidence
Lhasa requires Chengdu (cannot fly to Lhasa from Beijing without first flying to Chengdu).
Chengdu requires Xian (must fly to Xian before flying to Chengdu).
Evaluate
Parallel questions usually involve conditional logic, and when they do, we lean towards diagramming them symbolically to see their form.
The conditional arrow can be read as "requires", so when we have two premises telling us essentially that L requires C and that C requires X, we get a chain.
P: L → C P: C → X
Those chain together to show L → C → X
The conclusion is just giving us the head to tail connection of that chain: L → X
Goal
We want two conditional premises that chain together, and a conclusion that shows the head to tail connection of the chain.
P: A → B P: B → C C: A → C