If Suarez is not the most qualified of the candidates for sheriff, then Anderson is.
Conclusion (thus)
If the most qualified candidate is elected and Suarez is not elected, then Anderson will be.
Evidence
If Suarez is not the most qualified candidate for sheriff, then Anderson is.
Evaluate
There is conditional logic and repeating symbols within this argument, so it's a prime contender for diagramming with an algebraic recipe.
Premise: If X is not most Q, then Y is most Q. Conclusion: If most Q is selected and it's not X, then it must be Y.
But we could also get through this one conversationally. The premise is telling us that either S or A is the most qualified candidate.
Thus, if the most qualified candidate is selected, it will have to be S or A. Thus, if the most qualified candidate is selected and it's not S, then it must be A.
We could have alternatively concluded that
Goal
Look for a premise that gives you only two options for a certain thing. Then look for a conclusion that's saying, .